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10. In the figure above AD = 4, AB = 3 and CD = 9. What is the area of triangle AEC ? A. 18 B. 13.5 C. 9 D. 4.5 E. 3
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can you draw the picture first
The two triangles AEB and DEC are similar than \[ \frac {CD}{AB}=\frac {ED}{AE}= \frac 9 3\\ ED= 3 AE\\and\\ AD= 4\\then\\ AE=1\\ ED=3 \] Can you finish it now?
So if you now, label the picture with the given, do you see any useful info?
Area ACD = 9x4/2= 18 Area AED= 3x 9/2= 27/2=13.5 Area AEC= 18-13.5= 4.5
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