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Help! I need help getting rid of the y http://oi60.tinypic.com/244y5xz.jpg
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well how do u think u should do it @Nerdy_3000
I'm obviously very confused! I was trying to subtract the y from the other equation but it still doesn't make any sense
you have to fill y x and z in with annumber and ur answer has to be 4
Is the number 2 that I have to fill in
perfect yes
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\(\large \begin{array}{llll} x-y+2z=4\implies &x-y+2z=4\\ x-3z=1\implies &x{\color{blue}{ +0y}}-3z=1\\ 2y-z=-15\implies &{\color{blue}{ 0x}}+2y-z=-15 \end{array}\)
x-y+2z=4 ...(1) x-3z=1 ...(2) 2y-z=-15 ...(3) multiply (1) by 2 and add in (3) 2x+3z=-7 ...(4) solve (2) and (4) to get x and z. then put in (3) or (1) to get the value of y.
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