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13x-4[x+(3-x)]
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distribute the -4 and sum then sum any values
do you distribute it to the (3-x) also ?
well, no, you can just take it out, it has nothing to distribute over
\(\bf 13x{\color{red}{ -4}}[x+(3-x)]\implies 13x{\color{red}{ -4}}x-{\color{red}{ 12}}+{\color{red}{ 4}}x\)
oh ok I get it now, thank you!
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yw
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