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Algebra 20 Online
OpenStudy (anonymous):

1-cos^2x/sinxcosx

OpenStudy (anonymous):

start by replacing \(1-\cos^2(x)\) by \(\sin^2(x)\)

OpenStudy (anonymous):

cancel a sine top and bottom and you are left with \(\frac{\sin(x)}{\cos(x)}=\tan(x)\)

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