Find the differential(the the derivative) dy.
y=8tanx
dy = my answer that I got wrong was (8sec^2x+tanx)dx

then i need to Evaluate dy for the given values of x and dx. when x = pi/4 dx=-0.1

dy=

Question

Find the differential(the the derivative) dy.
y=8tanx
dy = my answer that I got wrong was (8sec^2x+tanx)dx

then i need to Evaluate dy for the given values of x and dx. when x = pi/4 dx=-0.1

dy=

anonymous · Answer

dy = 8sec^2(x)dx

anonymous · Answer

I thought you had to use product rule? so 8tanx = 8 tanx(prime) + tanx 8(prime)

dumbcow · Answer

technically yes however, derivative of 8 is 0 :)

anonymous · Answer

yes, thats why my answer is (8sec^2x+tanx)dx im confused on how im getting it wrong

dumbcow · Answer

no 8 prime is 0
tanx times 0 = 0

thats why answer is just 8sec^2

anonymous · Answer

:o

anonymous · Answer

my world became brighter lol, thank you!

dumbcow · Answer

lol yw

anonymous · Answer

do i just plug in pi/4 into x or do i have to convert it? @dumbcow

anonymous · Answer

i got -1.6 for part B

dumbcow · Answer

correct