Question

Find the value for sin(x/2) if following conditions hold:
tan(x) = -4/3 and x is in quadrant IV
a. -sqrt(5)/5
b sqrt(5)/5
c. 2sqrt5)/5
D. -2sqrt(5)/5

Answer 1

tanx = -4/3
as u know
tanx = perpendicular/base
so
we are going to determine hypotenuse
by using pythagoras theorem
h^2 = 4^2 + 3^2
h^2 = 16+9
h^2= 25
h=5
is all steps clear?