Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

What are the solutions to the equation f(x) = g(x)? x = -1, 5.4 x = -3, 4 x = -1, 2 x = -10, 12

OpenStudy (anonymous):

OpenStudy (anonymous):

@noseboy908 please help me

OpenStudy (noseboy908):

Gladly. So, look on your given graph, and tell me this: at what x values do the graphs of "f(x)" and "g(x)" intersect?

OpenStudy (anonymous):

they intersect at (-1,-10) and (5,11) right?

OpenStudy (noseboy908):

Well, to be precise, the second x value should be slightly bigger. So, given your two points, what is your answer?

OpenStudy (anonymous):

(-4,1)??? Sorry I'm not very good at math

OpenStudy (noseboy908):

Not to worry, just restate the x values of the points you found where the two graphs intersected. Be as precise as possible.

OpenStudy (anonymous):

sorry i hv no idea what it is?

OpenStudy (noseboy908):

Restate the points you already gave me (from when you said "they intersect at (-1,-10) and (5,11) right?"

OpenStudy (anonymous):

yea look i dont mean 2 rush but i really need this answer.

OpenStudy (anonymous):

i think its the 2nd one tho.

OpenStudy (noseboy908):

Just tell me this: given that an ordered pair is just "(x,y)", tell me the two x values from the points I just restated for you.

OpenStudy (anonymous):

-1, 5

OpenStudy (noseboy908):

And given that it's actually just over 5, what possible answer has those two x values?

OpenStudy (anonymous):

1st one?

OpenStudy (jdoe0001):

look at your choices, only 2 of them have a -1 x = -1, 5.4 <----- x = -3, 4 x = -1, 2 <---- x = -10, 12 so which one do you think are the values for "x" ?

OpenStudy (anonymous):

1???

OpenStudy (jdoe0001):

yeap, that'd be the likely one

OpenStudy (anonymous):

thnxs a bunch :)

OpenStudy (jdoe0001):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!