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How long does it take a ball to reach the ground 7.0 m below if thrown straight up with initial speed of 2.00m/s? i got time=? g=9.8m/s^2 d=7.0m iv=2.0m/s equation:ivt + 1/2 at^2 7.00m=(0m/s) + (0.5) (9.8) is this correct so far?
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@Isaiah.Feynman
Give me a minute.
no prob
This is quite different from the rest. This involves steps.
is this more advanced physics?because i looked this up online
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and im not in an advamced physics level
No its not advanced, its just free fall acceleration.
aw k
if u are unsure i can probably skip that one
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