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Mathematics 10 Online
OpenStudy (anonymous):

6e^2t = 3e^(t+1)

OpenStudy (anonymous):

What are you trying to do?

OpenStudy (gorv):

\[6*e^(2t)=3*e^(t+1)\]

OpenStudy (gorv):

\[6*(e^t)^2=3*e^t+3*e^1\]

OpenStudy (gorv):

\[6*(e^t)^2-3*e^t+3*e=0\]

OpenStudy (gorv):

now let e^t=x \[6*x^2-3*x+3*e=0\]

OpenStudy (gorv):

take 3 common

OpenStudy (gorv):

\[2*x^2-x+e=0\]

OpenStudy (gorv):

e =2.71 standard value now find solution of this quadratic equ.

OpenStudy (gorv):

if any assistance required contact

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