Keeping the voltage of the the charging source constant, what would be the percentage change in the energy stored
in a parallel plate capacitor if the separation between its plates were to be decreased by 10%?

Question

Keeping the voltage of the the charging source constant, what would be the percentage change in the energy stored
in a parallel plate capacitor if the separation between its plates were to be decreased by 10%?

anonymous · Answer

$$C=  \frac{A \epsilon }{ d }  $$

D is decreased  to 9/10th of it's original value. 

Energy stored is given by $$\frac{ 1 }{ 2 } C V^{2}$$

Take the ratio of initial and final energies to get your answer

anonymous · Answer

Final - Initial 
____________     x 100
    Intial

should give you the percentage change if I remember correctly.

anonymous · Answer

yeah, thanks i happen to have got the answer just before your message.