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the sum of first 16 terms of an A P is 528 and OF NEXT 16 TERMS IS 1552 . FIND FIRST TERM AND COMMON DIFFERENCE
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Let \(a_1\) be the first term and r b the common difference then \[ a_n= a_1 + (n-1) r \]
BUT CAN'T APPLY IT IN THIS PROBLEM
Why?
THE FIRST 16 TERM WILL HAVE ADIFF FIRST TERM AND THE NEXT 16 WILL HAVE SOME OTHER FIRST TERM
You do the sum of the first 16, then the sum of the first 32 and you take the difference
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The sum of the first k terms can be calculated to be \[ \sum_{n=1}^k a_n= k a_1+r\frac{1}{2} (k-1) k \]
If k=16, then, the sum is \[ 16 a_1 + 120 r \]
THANK YOU GOT THE ANSWER
YW
What did you get for r and a_1
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