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OpenStudy (anonymous):
integral (4x^2+3x-2)/((x-2)(x^2+1)), i got 4lnabs(x-2)-(1/2)(12)lnabs(x^2+1)+tan^-1(x/3). Can someone check if this is right
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OpenStudy (anonymous):
Check again! I could tell you the answer is 3tan^-1(x) +4ln|x-2|
OpenStudy (anonymous):
i tried multiple times, but still got the same answer, i don't know what i did wrong
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