Question

Which of the following is not a way to represent the solution of the inequality 3(2x - 1) greater than or equal to 4(2x - 3) - 3?

x less than or greater to 6

6 greater than or equal to x

A number line with a closed circle on 6 and shading to the left

A number line with a closed circle on 6 and shading to the right

Answer 1

help

Answer 2

sooo its
\[3(2x-1)\ge 4(2x-3) -3\]
\[6x-3 \ge 8x-12-3\]
\[6x \ge 8x -12\]
\[-2x \le -12\]
\[x \ge 6\]
x less than or greater to 6
A number line with a closed circle on 6 and shading to the left

Answer 3

thanks.

Answer 4

can you help me in other one

Answer 5

please

Answer 6

Uhm o.o okay

Answer 7

Solve for x.

-ax + 3b > 5

x > the quantity 3 times b minus 5 all over negative a

x > the quantity 5 minus 3 times b all over negative a

x < the quantity 3 times b plus 5 all over negative a

x < the quantity negative 3 times b plus 5 all over negative a

Answer 8

x < the quantity 3 times b plus 5 all over negative a