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Calculus1
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indefinite integral (cos(radx))/rad(x) dx
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\(\Large\bf \color{#008353 }{\text{Welcome to OpenStudy! :)}}\)
\[\Large\bf\sf \int\limits \frac{\cos \sqrt x}{\sqrt x}dx\]
\[\Large\bf\sf =\quad \int\limits \cos \sqrt x\left(\frac{1}{\sqrt x}\;dx\right)\]
Let \(\Large\bf\sf u=\sqrt x\)
\[\Large\bf\sf du=?\]
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1/2√x ?
but how do i work with the cosine part?
plug the value of \[\sqrt{x},\frac{ 1 }{ \sqrt{x} }~dx~ and~ integrate.\]
so is the answer 4*sin√x + C ?
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