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Calculus1
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Write the equation for the tangent line to the function at the given x- value.
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\[y= \ln (x+e ^{-4x})\]
x=0
first you have to differentiate y
Do you mean dy/dx
yeah
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are you know?
Do you mean new or do I know?
are you able to get dy/dx ?
Do you mean dy/dx
yes
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\[dy/dx= \frac{ 1-4e ^{-4x} }{ x+e ^{-4x} }\]
i think ti is not correct
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