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Mathematics 21 Online
OpenStudy (anonymous):

Solve for x in terms of a, the inequality |x²-3ax+2a²| < |x²+3ax-a²|, where x includes all real numbers, a≠0

OpenStudy (anonymous):

if this is on homework, don't do it if this a test question, don't do it either XDD

OpenStudy (anonymous):

you'll go crazy trying to solve it

OpenStudy (anonymous):

Either this will help\[ |a|<|b| \implies |a|^2<|b|^2\implies a^2<b^2 \]Or you will have to consider the 4 cases where either side is positive or negative.

OpenStudy (anonymous):

Also \[ |x^2-3ax+2a^2 |= |(x^2+3ax-a^2)+(6ax-3a^2)| \]

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