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use substitution to solve the system: 15x- = 5y + 5 y = 2x + 1 A. (5, 3) B. (5, -2) C (2, 3) D (2, 5)
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@triciaal @ashleydavidson939 @salparadise64
substitution 15x = 5(2x +1) + 5 15x = 10x + 5 + 5 5x = 10 x = 2
now you have x = 2 put this in the eqn for y y = 2x + 1 = 2*2 + 1 = 5 solution x =2 y = 5 d =(2,5)
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