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Solve by using the quadratic formula to solve x2 + 6x = -3.
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is it x^2
oops! sorry! Yeah I meant x²
lol yuperxzzz close enough XD
hahaha :)
Add 3 to both sides and set = to 0 \[\large x^2 + 6x + 3 = 0\] Coefficients are a = 1 b= 6 c = 3 \[\large \frac{-b \pm \sqrt{b^2 - 4ac)}}{2a}\] Plug in your numbers and solve :)
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BTW: WELCOME TO OPENSTUDY!!!!! *^.^*
aww thank you! Its amazing so far! :)
Thank you John!
Anytime :)
well maybe uve only been on for like an hour XD
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hahaha
But if u need anyhelp u can jus message me or tag me Tag people by pressing "@' then tyoe in the user name of the person u need help from, after u fan them *^.^*
okay :) Thanks so much!!
UR VERY WELCOME!!! ANYTIME!!! *^.^*
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