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Quadratic Question !!!! Help PLZZ !!! 7x^4−33x^2+26=0 Answers are : a.) 1.93,1 b.)1.86, –1.86, 1, –1 c.) 3.71, 1 d. 1.93 , - 1.93 ,1,-1
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(x^2 -1)(7x^2 -26) so x=+1,-1 \[x=\pm 1,\pm \sqrt{\frac{ 26 }{ 7 }}\]
sorry i write x=+1 and -1 twice
So does that make it d.) ????
you calculate sqrt(26/7)?
yes d is your answer
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Thank you soooo much sir you will be fanned !
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