Question

A student made the table shown below to prove that PQ is equal to RQ.


Statements Justifications
SQ = TQ
Given
m∠SQP = m∠TQR
Given
m∠RSQ = m∠PTQ
Given
m∠SQR = m∠SQP + m∠PQR
Angle Addition Postulate
m∠TQP = m∠TQR + m∠PQR
Angle Addition Postulate
m∠TQP = m∠SQP + m∠PQR
Substitution
m∠SQR = m∠TQP
Transitive Property
PQ = RQ
CPCTC