Question

If (w+3)(2w-a) = bw^2 - w + 3c, then the value of a-b+c will be

A) 7
B) -7
C) 8
D) -9
E) -2
'w' maybe OMEGA, but i am not sure.. Help!

Answer 1

\[\left( w+3 \right)\left( 2w-a \right)=bw^2-w+3c~or~2w^2+6w-aw-3a=bw^2-w+3c\]
2=b
-1=6-a
-3a=3c
from these equations find the values of a,b,c.

Answer 2

thanks...

Answer 3

yw