Question

A marble is drawn from a bag containing 3 red marbles and 2 blue marbles and a number cube with faces numbered 1 through 6 is tossed.

What is the probability that the marble drawn is blue and the number cube shows a number less than 3?

A marble is drawn from a bag containing 3 red marbles and 2 blue marbles and a number cube with faces numbered 1 through 6 is tossed.

What is the probability that the marble drawn is blue

A.11/15
B.1/4
C.1/6
D.2/15

Answer 1

The probability that he will draw a blue marble
\[ \frac{ \text{ blue marbles }}{\text{ total amount of marbles }}=\frac{2}{5}\]

Answer 2

The probability that the die will land on a number less than 3 namely 1 or 2 is
\[ \frac{2}{6}\]

Answer 3

2/5 isnt in here though

Answer 4

So the probability that both will occur is (2/5)*(2/6)

Answer 5

its 1/6

Answer 6

Ummm use you calculator if you cant multiply fractions -.-

Answer 7

ok wait

Answer 8

\[\frac{2}{5}*\frac{2}{6}=\frac{4}{30}=\frac{2}{15}\]

Answer 9

Anyways Im out