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OpenStudy (anonymous):
Help me with a 45-45-90 triangle? I need someone to walk me through/teach me how to solve this problem..
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OpenStudy (anonymous):
Solve for x and y. It's a 45-45-90 triangle, and one leg is sqr rt 2.I think x (the other leg ) would then be square root 2 but I am not sure
OpenStudy (anonymous):
in 45-45-90 triangle 2 sides are same and third one is different. Sides opposite 45-45 are same.
OpenStudy (anonymous):
It looks like this
@zepdrix
OpenStudy (anonymous):
if sides opposite 45-45 are X , then hypotenuse is X sq.rt 2
zepdrix (zepdrix):
|dw:1393892831088:dw|
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OpenStudy (anonymous):
@zepdrix yup that's what it looks like
@rukhsar What do you mean X square root 2?
OpenStudy (anonymous):
\[\sqrt{2}\] X
OpenStudy (anonymous):
Does that mean x (the other leg) would be \[\sqrt{2}\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Y = sq.rt 2 multiply by sq.rt 2
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OpenStudy (anonymous):
it's the property of 45-45-90 triangle
OpenStudy (anonymous):
\[\sqrt{2} \sqrt{2}\]
OpenStudy (anonymous):
so Y= 2
OpenStudy (anonymous):
so
\[\sqrt{2} multiply \sqrt{2} would that equal \sqrt{4}\]
OpenStudy (anonymous):
yes and sq.rt 4 = 2
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OpenStudy (anonymous):
Ah! I see, thank you so much! I was really struggling understanding it, I think I understand it now!
OpenStudy (anonymous):
np
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