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Which are the coordinates of the vertex of the graph of the function y= -x^2 + 6x -11?
A.) (3,-2) B.) (3,16) C.) (-3,-29) D.) (-3,-20)
X= -b/2a = -6/ -1*2 = 3
and with x substitute in the main function with x = 3 y=\[-(3)^{2} + (6 \times 3) \] =-2
the answer is a (3 , -2)
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