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OpenStudy (anonymous):
3 cards are drawn from a standard deck of cards. what is the probability of getting at least 2 kings?
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OpenStudy (kropot72):
\[P(2\ kings)=\frac{4C2\times48}{52C3}\] \[P(3\ kings)=\frac{4C3}{52C3}\] The required probability is the sum of the above two values of probability. Do you understand?
OpenStudy (kropot72):
@arest86 Are you there?
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