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Lucy found that a solution of x = - 4 was extraneous for her function. What would be a possible denominator in Lucy's function? A) x2 + 3x - 4 B) x2 - 9 C) x + 5 D) x - 4
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probably the first one since it is the same as \((x+4)(x-1)\) which cannot have \(x=-4\) as that would make the denominator zero
well ok then haha ty
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