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Mathematics 16 Online
OpenStudy (vera_ewing):

.

OpenStudy (anonymous):

can u tell me what the lengths of AB,BC,and AC ?

OpenStudy (anonymous):

BC=12 ?? how

OpenStudy (anonymous):

no 6 units only

OpenStudy (anonymous):

from -3 to 3

OpenStudy (anonymous):

ok so AC will be?

OpenStudy (anonymous):

AC=\[\sqrt{AB ^{2}+BC ^{2}}\]

OpenStudy (anonymous):

how you get AC=14?

OpenStudy (anonymous):

no are you know Pythagorean Theorem

OpenStudy (anonymous):

173.06

OpenStudy (anonymous):

no sorry wait

OpenStudy (anonymous):

31.21 that is the perimeter

OpenStudy (anonymous):

anytime :)

OpenStudy (anonymous):

who ?

OpenStudy (anonymous):

how ?*

OpenStudy (anonymous):

the distance=\[\sqrt{(-4-6)^{2}+)(8+12)^{2}}\]

OpenStudy (anonymous):

by calculator

OpenStudy (anonymous):

22.36

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

5

OpenStudy (anonymous):

5.83

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

10.29 for #5

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