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can u tell me what the lengths of AB,BC,and AC ?
BC=12 ?? how
no 6 units only
from -3 to 3
ok so AC will be?
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AC=\[\sqrt{AB ^{2}+BC ^{2}}\]
how you get AC=14?
no are you know Pythagorean Theorem
173.06
no sorry wait
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31.21 that is the perimeter
anytime :)
who ?
how ?*
the distance=\[\sqrt{(-4-6)^{2}+)(8+12)^{2}}\]
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by calculator
22.36
yea
ok
5
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5.83
yes
10.29 for #5
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