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Evaluate Sin^-1(aquare roote of 3/2)
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let \[\sin^{-1} \sqrt{\frac{ 3 }{ 2 }}=\] theta
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\[\sin \theta=\sqrt{\frac{ 3 }{ 2 }}\]
what is the angle that its sin is squaroot 3/2
theta=60 degrees
or 240 degrees
wait let me check
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its 120 degrees
yes this also can be right
and sorry 240 degrees is false
it's 60 and 120 degrees
Thank you
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