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integration of sin^4(3t) dt
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Even powers of sine and cosine are a little tricky. You can either apply the `Half-Angle Identity` a few times, Or you can apply the `Sine Reduction Formula`. Half-Angle is probably the way to go on this one since it's only 4th power.
Half-Angle Identity for Sine, \[\Large\bf\sf \sin^2x\quad=\quad \frac{1}{2}\left(1-\cos2x\right)\]
\[\Large\bf\sf \sin^43t\quad=\quad [\sin^23t]^2\quad=\quad \left[\frac{1}{2}\left(1-\cos6t\right)\right]^2\]
Understand how I applied it to this problem? :o
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