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Help please!! simplify (1 -sinα)/(1+sin(90°-α))
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sin(a-b) = sin(a)cos(b) - sin(b)cos(a)
soo \[\sin (90 - \alpha) =\sin90* \cos \alpha - \sin \alpha *\cos 90 \]
sin 90 = 1 & cos 90 = 0 sin (90 - alpha ) =cos (alpha)
then how about simplify 1-sin (alpha) / 1+cos (alpha) ?
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