Question

4(4k+2)-8(k-2)>3(2k+4)-1

Answer 1

expand the brackets

Answer 2

hwo would i do that? i dont know how to do this ?

Answer 3

well the first term 4(4k+2)

becomes 4*4k+4*2

Answer 4

can you simplify this ?

Answer 5

well yeah but i got it wrong on my test

Answer 6

what do you get when you simplify

4(4k+2)= 4*4k+4*2=

Answer 7

4(4k+2)=16k+8

Answer 8

good,

now expand the brackets and simplify the text term

-8(k-2) = =

Answer 9

-8(k-2)=16k+8=6k+12-1 right?

Answer 10

nope
-8(k-2) =-8*k+-8*-2 =

Answer 11

try again

Answer 12

well sorry but i cnt get it

Answer 13

for solving the whole problem i got k=2

Answer 14

Did u get it?

Answer 15

4(4k+2)-8(k-2)>3(2k+4)-1 Distribute by multiplying
16k+8-8k+16 > 6k+12 -1 Combine like terms
8k+24 > 6k + 11 Subtract 6k from both sides
-6k -6k(they cancel each other out)
2k+24> 11 Subtract 24 from both sides
-24 -24
2k > -13 Divide both sides by 2
k > -13/2 Answer

Answer 16

Any q's ? :D

Answer 17

best response ?

Answer 18

The symbol with line under it is an equal to so, u would write
k >= -13/2

Answer 19

@cmenendez55 ????? I have to go ...