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A flat rectangular piece of aluminum has a perimeter of 70 inches. The length is 11 inches longer than the width. Find the width.
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let width w=x in length l=x+11 in perimeter=2(x+11+x)=72 2x+11=72/2=36 x=?
Did you read what surjithayer wrote?
2x+11=72/2=36
So 2x+11=36?
Nevermind. What he wrote is incorrect.
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Oh
soy perimeter is 70 correction2x+11=70/2=35
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