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Can a tangent with the slope -(1/2) be drawn on the curve y=log4x ( that's a base 4). Explain, with calculus.
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yes, set f'(x) = -1/2
Sorry but could you further explain
do you know how to find derivative of log_4(x) ?
not really, is it 1/xln4?
very good. set 1/[x ln(4) ] = -1/2 and solve for x
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wait why do you set them equal to each other?
because you're try to find the where on the graph is the slope -1/2
m okay I got x=-2/ln4 is that correct?
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