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Find an equation of the tangent line to: y=1/Sqrt[x] at x=9 ?
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Slope, tangent, derivative. ;o
\[y=\frac{1}{\sqrt{x}}\]\[y=x^{-1/2}\]\[\frac{dy}{dx}=-\frac{1}{2}x^{-3/2}\]
Find the derivative of the function first, and then substitute the value of x to find the slope of the tangent line. To form an equation of a line you need a slope and a point--you know the x-value fr the point, all you need is the y. ^^ Then boom, y=m(x-p)+q and you have your equation
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