The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64.

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32.

Question

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64.

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32.

anonymous · Answer

@johnweldon1993 help please^.^ sorry...

johnweldon1993 · Answer

Well you know that the perimeter would be 2L + 2W...

is L = 20 and W = 11...that would be 2(20) + 2(11) = 40 + 22 = 62

So no it cannot...x + y does not equal 32...

anonymous · Answer

So B

johnweldon1993 · Answer

Never apologize hun That's correct :)