Question

y=ln l4x^2-9xl Find the derivative of function

Answer 1

we will use chain rule over here
\[\frac{ dy }{ dx } = \frac{ 1 }{ 4x^2-9x } *\frac{ d }{ dx }(4x^2-9x)\]

Answer 2

\[\frac{ 1 }{ 4x^2-9x }* (8x-9)\]

Answer 3

Whats the next step
And how did you got 8x?

Answer 4

ok look at this step\[4\frac{ d }{ dx }x^2 = 4*2x = 8x\]
is this step clear to you?

Answer 5

no

Answer 6

do u know \[\frac{ d }{ dx } x^n = n*x^{n-1}\] ????????

Answer 7

yes

Answer 8

so i used this concept in differentiating 4x^2

Answer 9

okay