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cos(3x)=-1 1.) Using an appropriate inverse trig expression, write an equation that defines the value of 3x 2.) Solve this equation to find all possible values of the angle 3x 3.) Use algebra to find all values of x between 0 and 2pi that satisfy this equation
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\(\bf cos(3x)=-1\quad \textit{taking }cos^{-1}\textit{ to both sides} \\ \quad \\ cos^{-1}[cos(3x)]=cos^{-1}(-1)\implies 3x=cos^{-1}(-1)\) 2) find all angles whose cosine is -1 3) solve for "x"
Okay I think I understand but how do I solve for x? Can you help me with that please?
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