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Mathematics 57 Online
OpenStudy (anonymous):

4/3 * 3.14 * 64 I can not figure this out the problem is http://puu.sh/7kb8H.png Can anyone help?

OpenStudy (jdoe0001):

what did you get?

OpenStudy (anonymous):

200.96

OpenStudy (jdoe0001):

hmm \(\bf \textit{volume of a sphere}=\cfrac{4\pi {\color{blue}{ r}}^3}{3}\qquad {\color{blue}{ r}}=4\implies \cfrac{4\pi ({\color{blue}{ 4}})^3}{3} \\ \quad \\ \cfrac{4\cdot 3.14 \cdot {\color{blue}{ 64}}}{3}\) what about for that one?

OpenStudy (anonymous):

That seems to be right besides that fact that you are dividing everything by 3 It does not show that here as part of the formula

OpenStudy (anonymous):

So where did I go wrong?

OpenStudy (jdoe0001):

\(\bf \cfrac{a}{b}\cdot whatever\implies \cfrac{a\cdot whatever}{b}\)

OpenStudy (jdoe0001):

or you can say \(\bf \cfrac{a}{b}\cdot whatever\implies \cfrac{a}{b}\cdot\cfrac{whatever}{1}\implies \cfrac{a\cdot whatever}{b\cdot 1}\)

OpenStudy (anonymous):

Okay but can you tell me what you got?

OpenStudy (anonymous):

Im obviously confused and this isnt really helping sine I still dont know the answer. If I knew it I could go back and see where I went wrong.

OpenStudy (jdoe0001):

\(\bf \cfrac{4\cdot 3.14 \cdot {\color{blue}{ 64}}}{3}=267.94666666666666666667 \)

OpenStudy (anonymous):

Wow thans I see now

OpenStudy (anonymous):

So I take the 3 from the 3/4?

OpenStudy (jdoe0001):

hmm you mean 4/3? the denominator ends up at the bottom of all other factors

OpenStudy (anonymous):

Oh yes sorry the 4/3. Wow okay thanks I see now

OpenStudy (jdoe0001):

keep in mind that \(\bf \cfrac{a}{b}\cdot u\cdot x\cdot z\implies \cfrac{a}{b}\cdot\cfrac{u}{1}\cdot \cfrac{x}{1}\cdot \cfrac{z}{1}\implies \cfrac{a\cdot u\cdot x\cdot z}{b\cdot 1\cdot 1\cdot 1}\implies \cfrac{a\cdot u\cdot x\cdot z}{b}\)

OpenStudy (anonymous):

Thanks I Will man you really just helped me through this section with that simple tip.. My teacher couldnt even do that.

OpenStudy (jdoe0001):

yw

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