Question

please help? 'find the next three terms of the arithmetic sequence: 39, 50, 61, 72 ...'

Answer 1

Add 11

Answer 2

72 + 11= 83
83 + 11= 94
94+ 11= 105

Answer 3

haha. I figured it out. srry.. I wasn't thinking stright..

Answer 4

Find the difference, 61-50 = 11 72-61 = 11

And so on, the difference is 11,

formula is a_n = a_1 + d(n - 1)

a_5 = 39 + 11(5 - 1)
a_5 = 39 + 11(4)
a_5 = 39 + 44
a_5 = 83

So the fifth term is 83, you can continue doing so for the remaining 2 digits if you like.

Answer 5

Using the Table function from Mathematica:
Table[ 39+11(n-1), {n, 7} ] -> {39, 50, 61, 72, 83, 94, 105}