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Select the correct function with the following transformations of the graph of y = x^2: shifted left 1 and up 3.
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The one with the vertex of the parabola at (-1,3) instead of (0,0).
y = (x - 1)^2 + 3 is this the answer?
Does the vertex look like it ends up where the two grid lines I've added to the graph intersect? If so, then that is the correct answer.
Hint: the parabola equation in vertex form is \[y = a(x-h)^2 + k\] where the vertex is at \((h,k)\) Those pesky - signs are the work of the devil, or so mathematicians used to believe :-)
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