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Mathematics 16 Online
OpenStudy (anonymous):

can someone solve and explain this to me please! A particle moves on a vertical line so that its coordinate at time t is s(t)= t^3 - 12t + 3 when t >/= 0? a. Find the velocity v(t) and acceration a(t). b. What is the meaning of v(t) > 0? What is the meaning of v(t) < 0? c. What is the meaning of a(t) > 0? What is the meaning of a(t) < 0?

OpenStudy (anonymous):

a) v(t)=s'(t) and a(t)=v'(t) b) draw a coordinate system. what direction does a positive velocity correspond to?

OpenStudy (anonymous):

okay i understand a but ihave no clue for b and c

OpenStudy (anonymous):

|dw:1394076531573:dw| as shown, when v(t)>0, the object moves up along the vertical line

OpenStudy (anonymous):

thanks alot

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