SOMEONE PLZ HELP W. THIS!!?
Solve 5 over x minus 5 equals the quantity of x over x minus 5, minus five fourths for x and determine if the solution is extraneous or not.
5 / (x -5) = x / (x -5) -5/4 Is that the equation?
Yes, that's it.
5 = x -5(x-5)/4
5 = x (-5x-25) / 4
oh ok, do I simplify further from here?
5 -x = (-5x -25) /4 20 -4x = -5x -25 20 + x = -25 x = -45
I don't know if that is correct or not.
Hm, well my choices are: x = -5, extraneous x = -5, non-extraneous x = 5, extraneous x = 5, non-extraneous
well if those are the choices, I must have done something wrong.
I don't know, I would have known how to solve this if it wasn't for the 4, because then you could multiply each part for the common denominator or something like that.:/ Idk how to solve this..
Should I just take an educated guess?
Maybe I can get rid of the 4 in the fraction. 20/(x-5) = 4x/(x-5) -5
Oh, cool and then divide the 20 by 4x?
No I think I solved it in my last post.
-5?
I'm guessing if x=-5 then the left side = -2 the right fraction = 2 then x= -5 ??????????????? I guess so.
Yes, it's just that simple -- LOL
lol, yea 'simple'.:) I'm taking a *52* question review test now, so even the simplest of problems are being tricky..lol thanks for you help:)
u r welcome
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