Question

Three consecutive even integers are such that the square of the third is 64 more than the square of the first. Find the integers using 5-step for problem solving

Answer 1

let n be our first integer
then three consecutive integers are
n,n+1,n+2
(n+2)^2=n^2+64

Answer 2

solve for n

Answer 3

can you do that @kaibull7 ?

Answer 4

thanks @zzr0ck3r

Answer 5

wouldnt the second integer be n+2 then n+4 because its asking for even integers? @zzr0ck3r