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Mathematics 7 Online
OpenStudy (anonymous):

help on C++ anyone?

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

It is declaring the method. So, it is the header (I believe). A call would not have defining these as returning specific type. Prototype would have the method's code as well.

OpenStudy (anonymous):

Let me ask what class you are taking?

OpenStudy (anonymous):

You declare functions/methods as: type name(arguments); You invoke / call functions as: name(value); You prototype functions/methods as: type name(arguments) { do x, y and z; return value of type; }

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