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help on C++ anyone?
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What is the question?
It is declaring the method. So, it is the header (I believe). A call would not have defining these as returning specific type. Prototype would have the method's code as well.
Let me ask what class you are taking?
You declare functions/methods as: type name(arguments); You invoke / call functions as: name(value); You prototype functions/methods as: type name(arguments) { do x, y and z; return value of type; }
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