Question

PLEASE HELP? two geometry questions i need help with? I need to know the number of terms, the first term, the last term, and then i need to evaluate the sum. ill post a pic

Answer 1

This is a sum notation, and the way it works is like this:\[\sum_{n=1}^{5}(3n+1)\] is the sum of 3n+1 for all n from n=1 to 5. So it's (3*1+1)+(3*2+1)+(3*3+1)+. . .

Answer 2

up to (3*5+1)

Answer 3

So the first term is 3+1, the second term is 6+1, the last term is 15+1, and the sum is 4+7+10+13+16=50.

Answer 4

can someone help with the second one?