1. For each of the following, assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, and Ace) in each of four suits (Clubs, Diamonds, Hearts, and Spades). a) What is the P(Club) when drawing one card? b) What is the P(Jack) when drawing one card? c) What is the P(Jack ∩ Club) when drawing one card? d) What is the P(Jack U Club) when drawing one card? e) What is the P(Jack|Face Card) when drawing one card? This roughly translates to what is the probability of getting a Jack if you know the card is a
a) The required probability is given by: \[\frac{number\ of\ clubs}{52}=you\ can\ calculate\]
is a face card. f) What is the P(Red|Heart) when drawing one card?
b) The required probability is given by: \[\frac{number\ of\ jacks}{52}=you\ can\ calculate\]
@Auztun Are you there?
yes im here!
Are you understanding so far?
so how do i know how many jacks there is?
The question says that there is one Jack in each of the four suits ( Jack of Clubs, Jack of Diamonds, Jack of Hearts and Jack of Spades).
@Auztun Do you now understand how many Jacks there are among the 52 cards?
4 right?
Correct! there are 4 Jacks in the pack.
so 4/52?
Yes, this is the solution to b). This can be simplified by dividing the numerator and the denominator by 4. Can you do that?
what is the numerator?
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ohhh haha duhhh okay what about part c?
and that would be the answer for b which is 13?
c) Do you understand the meaning of the cap (inverted U) symbol?
not at all
first time i have seen it
Are you learning statistics by self-study or taking a course?
no i am taking a course but have been behind schedule due to my grandmother passing and having to travel a great distance to pay my respects.
I suggest that you study your assigned textbooks to learn more of the basics before tackling questions such as this.
well i was hoping someone on here was able to attempt to show me how to do this cutting the time it will take to read a week of textbook
clueless
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