Question

Consider the function f(x)=6(x-2)^2/3. For this function there are two important intervals. Find critical number.
Can someone help me

Answer 1

well you need to solve

x - 2 = 0

this will be the critical value.

Answer 2

does solving what is inside the () always work ?

Answer 3

yep.... thats the zero... and since you are squaring the value, then taking the cube root the curve never goes below the x axis,

so it would look something like



hope it helps