factor 2x2-x-21=0
here is an easy method that works every time if you have a quadratic \[ax^2 + bx + c \] multiply a and c so in your question 2 * -21 = -42 find the factors of -42 that add to -1 hint: the larger factor is negative then write it as (ax + factor 1)(ax + factor 2) Yor question (2x + factor 1)(2x + factor 2) -------------------------- -------------------------- a 2 the binomials may have a common factor like (3x + 12) which can be written as 3(x + 4) and you'll find the common factor removed from the binomial will cancel with the denominator so in your question its (2x + 6)(2x - 7) -------------- 2 factor a binomial 2(x + 3)(2x - 7) -------------- 2 cancel the common factor, whats left is the answer
(2x-7)(x+3)
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