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^6sqrt(8a^3b^12) ?????????????
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∫ cos^2 3x dx you must use the half angle formula ∫ (1+cos 6x)/2 dx But I don't understand what happens after that. CalcChat.com says it turns into 1/2 ( x + 1/6 sin 6x) + C which turns into 1/12 (6x + sin 6x) + C What I don't understand is how ∫ (1+cos 6x)/2 dx turns into 1/2 ( x + 1/6 sin 6x) + C
its fine i have to figure this out eventually but thanks for your help i usually dont even get replies
u are so welcome
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