The equation of line CD is y = -2x - 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).
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OpenStudy (anonymous):
y = -2x + 13
y = -1/2x + 7
y = -1/2x + 3
y = − 2x − 3
OpenStudy (anonymous):
I know that the slope has to be the same.
OpenStudy (anonymous):
So either A or D
OpenStudy (anonymous):
parallel lines have the same slope...
then sub in pt. (4,5)
now you know that m=-2, x=4, and y=5...sub. into y=mx+b to find b
OpenStudy (anonymous):
to i have to input..
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OpenStudy (anonymous):
substitute m=-2, x=4, and y=5 to y=mx+b to find b
OpenStudy (anonymous):
im going with D
y = − 2x − 3
is this correct..
OpenStudy (anonymous):
did you solve it?
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
what did you get as b?
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OpenStudy (anonymous):
-3
OpenStudy (anonymous):
wrong
OpenStudy (anonymous):
how would i do it?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
substitute m=-2, x=4, and y=5 to y=mx+b to find b
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OpenStudy (anonymous):
b = 13
OpenStudy (anonymous):
@AntiNode
OpenStudy (anonymous):
so its A?
OpenStudy (anonymous):
@FlvsGirl
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
thanks a lot
i have 2 more easy questions if you can help
OpenStudy (anonymous):
did you understand how to get it?
OpenStudy (anonymous):
ok I will try
OpenStudy (anonymous):
The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (-3, 2).
y = 5x + 13
y = -1/5 x + 7/5
y = - 1/5 x -7/5
y = 5x - 17
OpenStudy (anonymous):
what will be the slope here?
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OpenStudy (anonymous):
-1/5
OpenStudy (anonymous):
now you have m=-1/5, x=-3, y=2...
as what we did before substitute these values in y=mx+b
OpenStudy (anonymous):
b = 7/5
OpenStudy (anonymous):
its B
OpenStudy (anonymous):
y = -1/5 x + 7/5
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